Throwout Bearing - Workings of...

Ok i give in, can someone explain it to me.....

It is mounted so it can slide away from the clutch on two pins and is pushed forward by 2 (not so strong) springs.

When the hydraulic fluid is applied and the centre section pushes forward to press against the clutch fingers all well and good, but what happens to the outer section it's not exactly held in place by anything solid. So the pressure from pushing on the clutch must equally cause the outer section to move away from the clutch and compress the 2 springs.

So what's going on ?

 

Many thanks, but that's not really the point of my question.

This video shows a typical "race" hydraulic release bearing, tilton has been making these for years. https://www.youtube.com/watch?v=2ST5wUHKCug

Note that outer do-nut (housing) position is fixed, it does not float on springs and the hydraulic feed is direct to it and not via the silly oil path F. came up with that needs multiple seals on the inside of the release bearing.


Clearly the springs don't really apply any significant pre-load (my biro has stronger springs - well almost). They will just keep the inner donut touching the clutch fingers.

The only reason i can see for the springs is that when the valve is open and the pressure released from the release bearing, the springs are just strong enough to push the outer donut forward effectively closing the donuts again and keeping the inner donut touching the fingers.


So when you want the clutch to be free....
the donuts must expand, so they push against the clutch fingers on one side and the springs on the other. The springs are much weaker and so the outer donut will move down the guide pins until eventually it hits the travel stop. At which point the expansion can then force the clutch fingers to move.

Well that's a lot of expansion needed before any movement of the clutch fingers takes place, plus the time it must take.

So why didn't F. just mount the Release bearing housing ?